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【简答题】
函数fun的功能是计算x的n次方。 double fun(double x,int n) {int i; double y=1; for(i=1;i<=n;i++) y=y*x; return y; } 主函数中已经正确定义 m 、 a 、 b 变量并赋值 , 并调用 fun 函数计算 :m=a^4+b^4-(a+b)^3 。实现这一计算的函数调用语句为______。
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参考答案：
举一反三
【单选题】设有变量 a 、 b 、 c 、 d 且都已正确定义并赋值。若有下列 if 语句: if(a if(c==d) y=0; else y=1; 该语句所表示的含义是 。
A.
当a
B.
当a
C.
当a
D.
当a
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
【单选题】设变量已正确定义并赋值，以下正确的表达式是______。
A.
x=y+z+5, + +y
B.
int(15.8%5)
C.
x=y*5=x+z
D.
x=25%5.0
相关题目：
【单选题】设有变量 a 、 b 、 c 、 d 且都已正确定义并赋值。若有下列 if 语句: if(a if(c==d) y=0; else y=1; 该语句所表示的含义是 。
A.
当a
B.
当a
C.
当a
D.
当a
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
【单选题】设变量已正确定义并赋值，以下正确的表达式是______。
A.
x=y+z+5, + +y
B.
int(15.8%5)
C.
x=y*5=x+z
D.
x=25%5.0
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