大学职业资格刷题搜题APP
创建自己的小题库
搜索
手机使用
分享
复制链接
新浪微博
分享QQ
微信扫一扫
反馈
收藏
举报
参考答案：
举一反三
【单选题】2016年7月12日,菲律宾诉中国南海仲裁案仲裁庭对“南海仲裁案”作出最终“裁决”,荷兰海牙法庭判菲律宾“胜诉”,声称中国对南海海域没有“历史性所有权”。中国政府回应:“仲裁庭裁决是非法无效的,中国不接受,不承认。中国的态度表明( )
A.
霸权主义和强权政治是解决和平与发展问题的主要障碍
B.
我国奉行独立自主的和平外交政策
C.
国家利益的对立是引起国家冲突的根源
D.
我国在维护自身利益时,兼顾他国合理关切
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
相关题目：
【单选题】2016年7月12日,菲律宾诉中国南海仲裁案仲裁庭对“南海仲裁案”作出最终“裁决”,荷兰海牙法庭判菲律宾“胜诉”,声称中国对南海海域没有“历史性所有权”。中国政府回应:“仲裁庭裁决是非法无效的,中国不接受,不承认。中国的态度表明( )
A.
霸权主义和强权政治是解决和平与发展问题的主要障碍
B.
我国奉行独立自主的和平外交政策
C.
国家利益的对立是引起国家冲突的根源
D.
我国在维护自身利益时,兼顾他国合理关切
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
参考解析：
题目纠错 0
发布
