给定程序中,函数fun的功能是将带头结点的单向链表逆置,即若原链表中从头至尾结点数据域依次为2,4,6,8,10,逆置后,从头至尾结点数据域依次为10,8,6,4,2。 #include #include #define N 5 typedef struct node { int data; struct node *next; } NODE; void fun(NODE *h) { NODE *p, *q, *r; p = h-> next; if (p== NULL) return; q = p->next; p->next = NULL; while (q) { r = q->next; q->next = p; /**********found**********/ p = q; q = ______; } h->next = p; } NODE *creatlist(int a[]) { NODE *h,*p,*q; int i; h = (NODE *)malloc(sizeof(NODE)); h->next = NULL; for(i=0; i { q=(NODE *)malloc(sizeof(NODE)); q->data=a[i]; q->next = NULL; if (h->next == NULL) h->next = p = q; else { p->next = q; p = q; } } return h; } void outlist(NODE *h) { NODE *p; p = h->next; if (p==NULL) printf("The list is NULL!\n"); else { printf("\nHead "); do { printf("->%d", p->data); p=p->next; } while(p!=NULL); printf("->End\n"); } } main() { NODE *head; int a[N]={2,4,6,8,10}; head=creatlist(a); printf("\nThe original list:\n"); outlist(head); fun(head); printf("\nThe list after inverting :\n"); outlist(head); }