大学职业资格刷题搜题APP
创建自己的小题库
搜索
手机使用
分享
复制链接
新浪微博
分享QQ
微信扫一扫
反馈
收藏
举报
参考答案：
举一反三
【单选题】单片机内部ADC模拟数字转换模块相关寄存器说法错误的是();
A.
P1口相应位作为ADC转换管脚时，需要将P1ASF中相应位置1；
B.
ADC转换控制寄存器 ADC_CONTR低3位用于选择模拟输入通道
C.
ADC转换结果格式控制由ADC_RES、ADC_RESL、AUXR1三个寄存器控制；
D.
IAP15W4K58S4单片机片内提供10个通道8位精度ADC采样
【单选题】下列选项中，不属于内容包装交换模型的内容的是()
A.
它是基于短消息的移动学习模式的延伸
B.
它有效地避因网络对学习者产生的负面影响
C.
它使学习者可以在脱机环境下学习
D.
它使学习者摆脱时间、地点的限制
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
相关题目：
【单选题】单片机内部ADC模拟数字转换模块相关寄存器说法错误的是();
A.
P1口相应位作为ADC转换管脚时，需要将P1ASF中相应位置1；
B.
ADC转换控制寄存器 ADC_CONTR低3位用于选择模拟输入通道
C.
ADC转换结果格式控制由ADC_RES、ADC_RESL、AUXR1三个寄存器控制；
D.
IAP15W4K58S4单片机片内提供10个通道8位精度ADC采样
【单选题】下列选项中，不属于内容包装交换模型的内容的是()
A.
它是基于短消息的移动学习模式的延伸
B.
它有效地避因网络对学习者产生的负面影响
C.
它使学习者可以在脱机环境下学习
D.
它使学习者摆脱时间、地点的限制
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
参考解析：
题目纠错 0
发布
