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【单选题】
在词汇教学中,以下输入与输出过程中的重点步骤正确的顺序是? 1接触新词2巩固记忆3活用词汇4理解词义了解词形
A.
①④②③
B.
①④③②
C.
①③②④
D.
①③④②
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参考答案：
举一反三
【多选题】Rh阴性的妇女(无妊娠史)第一次输入Rh阳性的血液可能
A.
产生Rh抗体
B.
红细胞发生凝集
C.
下次妊娠(胎儿若是Rh阳性)时胎儿可能出现溶血性贫血
D.
第二次再输Rh趾阳性血不会有反应
E.
可发生输血反应
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
【单选题】6 σ 质量水平通常是指输出过程的缺陷率为 ,是过程在 ()运行中出现缺陷的比率，以下正确的是( ) 。
A.
0.27% 长期
B.
0.27% 短期
C.
3.4ppm 短期
D.
3.4ppm 长期
相关题目：
【多选题】Rh阴性的妇女(无妊娠史)第一次输入Rh阳性的血液可能
A.
产生Rh抗体
B.
红细胞发生凝集
C.
下次妊娠(胎儿若是Rh阳性)时胎儿可能出现溶血性贫血
D.
第二次再输Rh趾阳性血不会有反应
E.
可发生输血反应
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
【单选题】6 σ 质量水平通常是指输出过程的缺陷率为 ,是过程在 ()运行中出现缺陷的比率，以下正确的是( ) 。
A.
0.27% 长期
B.
0.27% 短期
C.
3.4ppm 短期
D.
3.4ppm 长期
参考解析：
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