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【单选题】
颅脑损伤维持有效的循环功能措施不正确的是：()
A.
补充大量液体或生理盐水
B.
有效地止血
C.
快速地输血或血浆
D.
可选择加压包扎
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参考答案：
举一反三
【单选题】颅脑损伤患者出现下列症状即提示护士应立即做好术前准备的是
A.
呼吸深而慢
B.
库欣反应
C.
剧烈头痛、喷射性呕吐
D.
一侧瞳孔进行性散大，对侧肢体瘫痪
E.
腰穿抽出血性脑脊液
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
【单选题】维持子宫正常位置的是
A.
膀胱和直肠的支托作用
B.
腹腔压力作用
C.
子宫四对韧带的作用
D.
骨盆底肌肉及其上下筋膜支托作用
E.
子宫四对韧带及盆底肌肉筋膜的支托作用
相关题目：
【单选题】颅脑损伤患者出现下列症状即提示护士应立即做好术前准备的是
A.
呼吸深而慢
B.
库欣反应
C.
剧烈头痛、喷射性呕吐
D.
一侧瞳孔进行性散大，对侧肢体瘫痪
E.
腰穿抽出血性脑脊液
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
【单选题】维持子宫正常位置的是
A.
膀胱和直肠的支托作用
B.
腹腔压力作用
C.
子宫四对韧带的作用
D.
骨盆底肌肉及其上下筋膜支托作用
E.
子宫四对韧带及盆底肌肉筋膜的支托作用
参考解析：
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