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【单选题】
碳水化合物在身体内的主要功能是什么？
A.
建立细胞质
B.
修补已损坏的组织
C.
热能的来源
D.
储存元素
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参考答案：
举一反三
【单选题】碳水化合物提供热能占总热能（）
A.
1%～3%
B.
10%～12%
C.
12%～14%
D.
20%～30%
E.
55%～65%
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
【单选题】下列有关铁及其化合物的有关说法中正确的是（ ）
A.
赤铁矿的主要成分是Fe3O4
B.
铁与水蒸气在高温下的反应产物为Fe2O3和H2
C.
除去FeCl2溶液中的FeCl3杂质可以向溶液中加入铁粉，然后过滤
D.
Fe3+与KSCN产生血红色沉淀
【单选题】脂肪和碳水化合物,它们在体内的产热系数分别为:()
A.
4kCAl/g,9kCAl/g,9kCAl/g
B.
4kCAl/g, 9kCAl/g,4kCAl/g
C.
9kCAl/g,4kCAl/g,4kCAl/g
D.
4kCAl/g,4kCAl/g,4kCAl/g
相关题目：
【单选题】碳水化合物提供热能占总热能（）
A.
1%～3%
B.
10%～12%
C.
12%～14%
D.
20%～30%
E.
55%～65%
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
【单选题】下列有关铁及其化合物的有关说法中正确的是（ ）
A.
赤铁矿的主要成分是Fe3O4
B.
铁与水蒸气在高温下的反应产物为Fe2O3和H2
C.
除去FeCl2溶液中的FeCl3杂质可以向溶液中加入铁粉，然后过滤
D.
Fe3+与KSCN产生血红色沉淀
【单选题】脂肪和碳水化合物,它们在体内的产热系数分别为:()
A.
4kCAl/g,9kCAl/g,9kCAl/g
B.
4kCAl/g, 9kCAl/g,4kCAl/g
C.
9kCAl/g,4kCAl/g,4kCAl/g
D.
4kCAl/g,4kCAl/g,4kCAl/g
参考解析：
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